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Question

1/ $\left\{ \begin{array}{l} 3x-1 \geqslant 2x+7 \\ 4x+3 > 2x+19 \end{array} \right.$

2/ $\left\{ \begin{array}{l} \frac{2x+3}{x-1}\geqslant 1\\ \frac{(x+2)(2x-4)}{x-1}\leq 0\end{array} \right.$

3/ $\left\{ \begin{array}{l} x^{2}-x-12 <0 \\ 2x-1 >0 \end{array} \right.$

rang · Answer 1 · 2/16/2016 12:05:18 AM

$c/ \Leftrightarrow \left\{ \begin{array}{l} (x-4)(x+3)<0\\ x>\frac{1}{2} \end{array} \right.$

$\Leftrightarrow \left\{ \begin{array}{l} -3<x<4\\ x>\frac{1}{2} \end{array} \right.$

$\Leftrightarrow \frac{1}{2}<x<4$

Trả lời 16-02-16 12:05 AM

rang
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rang · Answer 2 · 2/16/2016 12:07:58 AM

$a/\Leftrightarrow \left\{ \begin{array}{l} 3x-1-2x-7\geq 0\\ 4x+3-2x-19>0 \end{array} \right.$

$\Leftrightarrow \left\{ \begin{array}{l} x-8\geq 0\\ 2x-16>0 \end{array} \right.$

$\Leftrightarrow \left\{ \begin{array}{l} x\geq 8\\ x>8 \end{array} \right.$

$\Leftrightarrow x>8$

Sửa 16-02-16 12:07 AM

rang
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Trả lời 16-02-16 12:02 AM

rang
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42K 72K

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