$(1+1)^n=C^0_n+C^1_n+C^2_n+...+C^n_n=2+C^1_n+C^2_n+...+C^{n-1}_n=4^{2014}$=> $2^n=4^{2014}$=> $2^n=2^{2015}$=> $n=2015$
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23-03-16 09:28 AM
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