$\left\{ \begin{array}{l} x^{2}-3x=33-y^{2}+4y\\ 3(x^{2}-3x)=3+2y^{2} +8y(*)\end{array} \right.$$(*)\Leftrightarrow 3(33-y^{2}+4y)=3+2y^{2}+8y\Leftrightarrow5y^{2}-4y-96=0\Rightarrow \left\{ \begin{array}{l} y=\frac{24}{5}\\ y=-4 \end{array} \right. $
Với y=$\frac{24}{5}\Rightarrow x^{2}-3x=\frac{729}{25}\Rightarrow \left\{ \begin{array}{l} x=\frac{15+3\sqrt{349}}{10}\\ x=\frac{15-3\sqrt{349}}{10} \end{array} \right.$
Với$ y=-4\Rightarrow x^{2}-3x=1\Rightarrow \left\{ \begin{array}{l} x=\frac{3+\sqrt{13}}{2}\\ x=\frac{3-\sqrt{13}}{2} \end{array} \right. $