bat dang thuc
su dung bat dang thuc chung minh cho cac BDT sau: a/
$\frac{1}{4a^{2} + 4b^{2}} + \frac{1}{8ab} \geqslant \frac{1}{(a + b)^{2}}
$ $\forall a, b
> 0
$b/
$\frac{1}{a} + \frac{1}{b} + \frac{1}{c} \geqslant \frac{4}{2a + b + c} + \frac{4}{2b + c + a} + \frac{4}{2c + a +b}
$ $\forall a, b, c
$ > 0
Bất đẳng thức
bat dang thuc
su dung bat dang thuc chung minh cho cac BDT sau: a/ \frac{1}{4a^{2} + 4b^{2}} + \frac{1}{8ab} \geqslant \frac{1}{(a + b)^{2}} \forall a, b
lon hon 0b/ \frac{1}{a} + \frac{1}{b} + \frac{1}{c} \geqslant \frac{4}{2a + b + c} + \frac{4}{2b + c + a} + \frac{4}{2c + a +b} \forall a, b, c
lon hon 0
Bất đẳng thức
bat dang thuc
su dung bat dang thuc chung minh cho cac BDT sau: a/
$\frac{1}{4a^{2} + 4b^{2}} + \frac{1}{8ab} \geqslant \frac{1}{(a + b)^{2}}
$ $\forall a, b
> 0
$b/
$\frac{1}{a} + \frac{1}{b} + \frac{1}{c} \geqslant \frac{4}{2a + b + c} + \frac{4}{2b + c + a} + \frac{4}{2c + a +b}
$ $\forall a, b, c
$ > 0
Bất đẳng thức