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lôgarit

Chứng minh rằng nếu $x>0,y>0$ và $x^2+4y^2=12xy$ thì $\log (x+2y)-2\log 2=\frac 12(\log x+\log y)$
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lôgarit

7Bình chọn giảmQuan tâm0Đưa vào sổ tay1" role="presentation" style="font-size: 13.696px; display: inline; line-height: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">11) Chứng minh rằng nếu x>0,y>0" role="presentation" style="font-size: 13.696px; display: inline; line-height: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">x>0,y>0x>0,y>0 và x2+4y2=12xy" role="presentation" style="font-size: 13.696px; display: inline; line-height: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">x2+4y2=12xyx2+4y2=12xy thì log⁡(x+2y)−2log⁡2=12(log⁡x+log⁡y)" role="presentation" style="font-size: 13.696px; display: inline; line-height: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">log(x+2y)−2log2=12(logx+logy)log⁡(x+2y)−2log⁡2=12(log⁡x+log⁡y)" role="presentation" style="font-size: 13.696px; display: inline; line-height: normal; word-spacing: normal; word-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">