$$\mathop {\lim }\limits_{x \to 2^+}\dfrac{4x^3-3}{2x^2+3x-2}=\frac{29}{12}$$
$$\mathop {\lim }\limits_{x \to 2^+}\dfrac{4x^3-3}{2x^2+3x-2}=\frac{29}{12}$$ (thay 2 vào thôi)
$$\mathop {\lim }\limits_{x \to 2^+}\dfrac{4x^3-3}{2x^2+3x-2}=\frac{29}{12}$$