Quay lại đáp án

	2	bớt 11 ký tự trong đáp án		Sửa 13-04-13 05:40 PM Cá Hêu 1
$(x-3)(x-5)(x-6)(x-10)-24x2=(x^2-13x+30)(x^2-11x+30)-24x2=P$Đặt $x^2-12x+30=t$$P=(t-x)(t+x)-24x^2$$P=t2-25x^2$ $=(t-5x)(t+5x)$ $=(x^2-17x+30)(x^2-7x+30)$ (x-3)(x-5)(x-6)(x-10)-24x2=(x2-13x+30)(x2-11x+30)-24x2=Pdat x2-12x+30=t>>>P=(t-x)(t+x)-24x2>>>P=t2-25x2 =(t-5x)(t+5x) =(x2-17x+30)(x2-7x+30) $(x-3)(x-5)(x-6)(x-10)-24x2=(x^2-13x+30)(x^2-11x+30)-24x2=P$Đặt $x^2-12x+30=t$$P=(t-x)(t+x)-24x^2$$P=t2-25x^2$ $=(t-5x)(t+5x)$ $=(x^2-17x+30)(x^2-7x+30)$

	1	tạo mới
(x-3)(x-5)(x-6)(x-10)-24x2=(x2-13x+30)(x2-11x+30)-24x2=Pdat x2-12x+30=t>>>P=(t-x)(t+x)-24x2>>>P=t2-25x2 =(t-5x)(t+5x) =(x2-17x+30)(x2-7x+30)

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