y' = (3x-8)'.sin(2x+5) + [sin(2x+5)]'.(3x-8) = 3sin(2x+5) + (2x+5)'.cos(2x+5).(3x-8) = 3sin(2x+5) + 2cos(2x+5).(3x-8)
y' = (3x-8)'.sin(2x+5) + [sin(2x+5)]'.(3x-8) = 3sin(2x+5) + (2x+4)'.cos(2x+5).(3x-8) = 3sin(2x+5) + 2cos(2x+5).(3x-8)Vài bước đơn giản xin được chia sẽ cùng bạn !
y' = (3x-8)'.sin(2x+5) + [sin(2x+5)]'.(3x-8) = 3sin(2x+5) + (2x+
5)'.cos(2x+5).(3x-8) = 3sin(2x+5) + 2cos(2x+5).(3x-8)