HPT$\Leftrightarrow \begin{cases}x+y^2=7-3x^2 \\ 3x+3y^2=11+4x^2 \end{cases}\rightarrow 3(7-3x^2)=11+4x^2=>x^2=\frac{10}{13}=>$$x=^+_-\sqrt{\frac{10}{13}}$với $x=\sqrt{\frac{10}{13}}=>y=............$với $x=-\sqrt{\frac{10}{13}}=>y=.........$
HPT$\Leftrightarrow \begin{cases}x+y^2=7-3x^2 \\ 3x+3y^2=11+4x^2 \end{cases}\rightarrow 3(7-3x^2)=11+4x^2=>x^2=\frac{10}9=>$$x=^+_-\frac{\sqrt{10}}3$với $x=\frac{\sqrt{10}}3=>y^2=\frac{11-\sqrt{10}}3=>y=............$với $x=-\frac{\sqrt{10}}3=>y^2=\frac{11+\sqrt{10}}{3}=>y=.........$
HPT$\Leftrightarrow \begin{cases}x+y^2=7-3x^2 \\ 3x+3y^2=11+4x^2 \end{cases}\rightarrow 3(7-3x^2)=11+4x^2=>x^2=\frac{10}
{13}=>$$x=^+_-\sqrt{
\frac{10}
{13}
}$với $x=\sqrt{\frac{1
0}{1
3}}=>y=............$với $x=-\sqrt{\frac{10}{
13
}}=>y=.........$