\[\left\{ {\begin{array}{*{20}{l}} {{u_1} + {u_2} + {u_3} = 27} \\ {u_1^2 + u_2^2 + u_3^2 = 275} \end{array}} \right.\]\[ \Leftrightarrow \left\{ {\begin{array}{*{20}{l}} {{u_1} + \frac{{{u_1} + {u_3}}}{2} + {u_3} = 27} \\ {u_1^2 + {{\left( {\frac{{{u_1} + {u_3}}}{2}} \right)}^2} + u_3^2 = 275} \end{array}} \right.\]⇔{u1+u3=18u21+u23=194⇔{u1+u3=18u1u3=65⇒u1,u3 là nghiệm của pt x2−18x+65=0\[ \Rightarrow \left\{ \begin{gathered} {u_1} = 13 \hfill \\ {u_3} = 5 \hfill \\ \end{gathered} \right. \vee \left\{ \begin{gathered} {u_1} = 5 \hfill \\ {u_3} = 13 \hfill \\ \end{gathered} \right. \Leftrightarrow \left\{ \begin{gathered} {u_1} = 13 \hfill \\ d = - 4 \hfill \\ \end{gathered} \right. \vee \left\{ \begin{gathered} {u_1} = 5 \hfill \\ {u_3} = 4 \hfill \\ \end{gathered} \right.\]
{u1+u2+u3=27u21+u22+u23=275⇔{u1+u1+u32+u3=27u21+(u1+u32)2+u23=275⇔{u1+u3=18u21+u23=194⇔{u1+u3=18u1u3=65⇒u1,u3 là nghiệm của pt
x2−18x+65=0\[ \Rightarrow \left\{ \begin{a
rr
ay}
{l}{u_1} = 13\\{u_3} = 5\end{ar
ray} \right. \vee \left\{ \begin{a
rr
ay}
{l}{u_1} = 5\\{u_3} = 13\end{a
rr
ay} \right. \Leftrightarrow \left\{ \begin{a
rr
ay}
{l}{u_1} = 13\\d = - 4\end{ar
ray} \right. \vee \left\{ \begin{a
rr
ay}
{l}{u_1} = 5\\{u_3} = 4\end{ar
ray} \right.\]