goi A(a,b) B(c,d)A\inAB=>a-b=-2=0=>a=b-2=>A(b-2,b)tuong tu nhu B(d-2,d)AB=4\sqrt{x}2<=>(d-b)^2+(d-b)2=16=>(d-b)^2=8=>d-b=2can2 hoac d-b=-2can2trong tam G cua tam giac G(1+b+d-4/3,5+b+d/3) thay toa do G vao pt dt d la ra...
goi
$A(a,b) B(c,d)
$$A
\in
AB=>a-b=-2=0=>a=b-2=>A(b-2,b)
$t
ương t
ự nh
ư $B(d-2,
đ)
$$AB=4\sqrt{
2}<=>(d-b)^2+(d-b)2=16=>(d-b)^2=8=>d-b=2
\sqrt{2
} o
r d-b=-2
\sqrt{2
}$tr
ọng t
âm G c
ủa tam gi
ác
$G(1+b+d-
\frac{4
}{3
},5+b+
\frac{d
}{3
})
$thay toa do G vao pt dt d la ra...