{(2x−1−−−−−−√−y)−2y2x−1−−−−−−√+8=0(2x−1−−−−−−√−y)2+3y2x−1−−−−−−√=14pt1.3+pt2.2: $2(\sqrt{2x-1}-y)^2+3(\sqrt{2x-1}-y)-4=0$
\begin{
cases}\sqrt{2x
-1
}-y
-2y
\sqrt{2x
-1
}+8=0
\\ (
\sqrt{2x
-1
}-y)
^2+3y
\sqrt{2x
-1
}=1
2 \end{cases}-1 pt1.3+pt2.2: $2(\sqrt{2x-1}-y)^2+3(\sqrt{2x-1}-y)=0$