do có dấu giá trị tuyệt đối nênKhi $x\geq \frac{1}{3}$ hoặc khi $x<\frac{1}{3}$ $\Rightarrow 1\tfrac{1}{2}x-\frac{1}{2}=\frac{1}{4}$ hoặc $\Rightarrow 1\tfrac{1}{2}x-\frac{1}{2}=\frac{-1}{4}$ $\Rightarrow x=\frac{\frac{1}{4}+\frac{1}{2}}{1\tfrac{1}{2}}$ $\Rightarrow x=\frac{\frac{-1}{4}+\frac{1}{2}}{1\tfrac{1}{2}}$$\Leftrightarrow x=\frac{1}{2}$(nhận) hoặc $x=\frac{1}{6}$(nhận)vậy $x=\frac{1}{2};\frac{1}{6}$
...$\Rig
ht
ar
row 1\t
frac{1}{2}.x
-\
frac{1}{2}=\frac{1}{
4}$ hoặc $
-\frac{1}{
4}$ $\Rightarrow 1\tfrac{1}{2}x-\frac{1}{2}=\frac{1}{4}$ hoặc $\Rightarrow 1\tfrac{1}{2}x-\frac{1}{2}=\frac{-1}{4}$ $\Rightarrow x=\frac{\frac{1}{4}+\frac{1}{2}}{1\tfrac{1}{2}}$ $\Rightarrow x=\frac{\frac{-1}{4}+\frac{1}{2}}{1\tfrac{1}{2}}$$\Leftrightarrow x=\frac{1}{2}$(nhận) $x=\frac{1}{6}$(nhận)
Vậy $x=\frac{1}{2};\frac{1}{6}$