$\frac 12=\frac 23(\frac 11-\frac 14)$$\frac 1{14}=\frac 23(\frac 14 -\frac 17)$...$\frac 1{4850}=\frac23(\frac 1{97}-\frac 1{100})$$\Rightarrow A=\frac 23(1-\frac 1{100})=\frac {33}{50}$
$A=\frac {33}{50}$
$
\frac 12=\frac 23(\frac 11-\frac 14)$$\frac 1{14}=\frac 23(\frac 14 -\frac 17)$...$\frac 1{4850}=\frac23(\frac 1{97}-\frac 1{100})$$\Rightarrow A
=\frac 23(1-\frac 1{100})=\frac {33}{50}$