Ta có : pt (\sqrt{3}\tan x -1)^2+(2\sin x-1)^2=0\Leftrightarrow ${tanx=1√3sinx=12 :)
Ta có : pt 3tan2⁡x+4sin2⁡x−23tan⁡x−4sin⁡x+2=0" style="position: relative;" tabindex="0" id="MathJax-Element-1-Frame" class="MathJax">(\sqrt{3}\tan x -1)^2+(2\sin x-1)^2=0\Leftrightarrow {tanx=1√3sinx=12 :)
Ta có : pt (\sqrt{3}\tan x -1)^2+(2\sin x-1)^2=0\Leftrightarrow
${tanx=1√3sinx=12 :)