limx→0⁡1−cos2⁡xsin⁡2x=limx→0⁡sin2⁡x2x.sin⁡x.cos⁡x=limx→0⁡sin⁡x2x.cos⁡x=limx→0⁡sin⁡xx.limx→0⁡12cos⁡x=1.12=12" role="presentation" style="font-size: 13.696px; word-spacing: 0px; position: relative;">limx→01−cos2xsin2x=limx→0sin2x2x.sinx.cosx=limx→0sinx2x.cosx=limx→0sinxx.limx→012cosx=1.12=12