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$\Leftrightarrow \begin{cases}x^2+6y^2= 2xy+4y-2y^2 (1)\\ x(x^2+6y^2)= y(4y+3x^2) (2)\end{cases}$
$\Leftrightarrow \begin{cases}x^2+6y^2 =2y(x+2-y)\\ 2xy(x+2-y)= y(4y+3x^2)\end{cases}$ (thế (1) vào (2))
$\Leftrightarrow [\begin{matrix} \begin{cases}x^2+8y^2= 2xy+4y\\ y=0 \end{cases}(3)\\ \begin{cases}x^2+8y^2=2xy+4y \\ 2x(x-y+2)=4y+3x^2 \end{cases}(4)\end{matrix}$
(3)$\Leftrightarrow x=y=0$
(4)$\Leftrightarrow \begin{cases}x^2+8y^2=2xy+4y \\ x^2+8x= 2xy+4y\end{cases}$
$\Leftrightarrow \begin{cases}x= y^2\\ x^2+8y^2=2xy+4y \end{cases}$
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