$\frac{\sqrt2+\sqrt3+\sqrt6+\sqrt8+\sqrt16}{\sqrt2+\sqrt3+\sqrt4}$
$=\frac{\sqrt2+\sqrt3+\sqrt6+\sqrt8+4}{\sqrt2+\sqrt3+\sqrt4}$
$=\frac{\sqrt2+\sqrt3+2+2+\sqrt6+\sqrt8}{\sqrt2+\sqrt3+\sqrt4}$
$=\frac{(\sqrt2+\sqrt3+\sqrt4)+(\sqrt4+\sqrt6+\sqrt8)}{\sqrt2+\sqrt3+\sqrt4}$
$=1+\sqrt2$