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$\left|x^2\left|x+\dfrac{3}{4}\right|\right|=x^2\\\Leftrightarrow x^2\left|x+\dfrac{3}{4}\right|=x^2\\\Leftrightarrow \left|x^2+\dfrac{3}{4}\right|=1\\\Leftrightarrow \left[ \begin{array}{l}x+\dfrac{3}{4}=1\\x+\dfrac{3}{4}=-1\end{array} \right.\\\Leftrightarrow \left[ \begin{array}{l}x=\dfrac{1}{4}\\x=-\dfrac{7}{4}\end{array} \right.$
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