$\sqrt{5x^2+2x+1}-5+\sqrt{2x^2+1}-3+\sqrt{x-1}+1=3x-6$$\frac{5x^2+2x+1-25}{\sqrt{5x^2+2x+1}+5}+\frac{2x^2+1-9}{\sqrt{2x^2+1}+3}+\frac{x-1-1}{\sqrt{x-1}+1}=3(x-2)$
$(x-2)[\frac{5x+12}{\sqrt{5x^2+2x+1}+5}+\frac{x+2}{\sqrt{2x^2+1}+3}+\frac{1}{\sqrt{x-1}+1}-3]=0$
$=> x=2$
xét DK $x>1 $ => trong ngoặc vô nghiệm
K THẤY J HAY HẾT