√5x2+2x+1−5+√2x2+1−3√x−1+1=3x−65x2+2x+1−25√5x2+2x+1+5+2x2+1−9√2x2+1+3+x−1−1√x−1+1=3(x−2)(x−2)[5x+12√5x2+2x+1+5+x+2√2x2+1+3+1√x−1+1−3]=0=>x=2xét DK x>1 => trong ngoặc vô nghiệmK THẤY J HAY HẾT
$\sqrt{5x^2+2x+1}-5+\sqrt{2x^2+1}-3+\sqrt{x-1}+1=3x-65x2+2x+1−25√5x2+2x+1+5+2x2+1−9√2x2+1+3+x−1−1√x−1+1=3(x−2)(x-2)[\frac{5x+12}{\sqrt{5x^2+2x+1}+5}+\frac{x+2}{\sqrt{2x^2+1}+3}+\frac{1}{\sqrt{x-1}+1}-3]=0$$=> x=2$xét DK $x>1 $ => trong ngoặc vô nghiệmK THẤY J HAY HẾT