$\left ( x-2 \right )^{2}\left ( 2x+5 \right )=\frac{5\left ( x-1 \right )-\left ( x^{2}+x-1 \right )}{\sqrt{x^{2}+x-1}}$=> $\left ( x-2 \right )^{2}\left ( 2x+5 \right )+\frac{\left ( x-2 \right )^{2}}{\sqrt{x^{2}+x-1}}=0$
=> $\left ( x -2\right )^{2}\left ( 2x+5+\frac{1}{\sqrt{x^{2}+x-1}} \right )=0$
giài cả hai pt ta dc :x=2 và x=-2.75