ta có $AB: 4x-3y-12=0;AB =\frac{20}{3}$SMAB=$\frac{1}{2}.d(M,AB).AB \Rightarrow d(M,AB)=4$
gọi $M (x;y) \Rightarrow \frac{\left| 4x-3y-12 \right|}{5}=4 \Leftrightarrow y=\frac{4x+32}{3} or y=\frac{4x-8}{3}$
thay vào đt(C) $\Rightarrow M(2;0) or M(\frac{14}{25};\frac{-48}{25})$