đặt $\sqrt{4x+3}+\sqrt{2x+1} =t \ge 0$
$\Leftrightarrow 6x +4 +2\sqrt{8x^2 +10x+3}=t^2$
PT đưa về $t^2 -t -20=0 \Rightarrow t=5 ;\ t=-4(loai)$
$ \Rightarrow 6x +4 +2\sqrt{8x^2 +10x+3}=25$
$\Leftrightarrow 2\sqrt{8x^2 +10x+3}=21-6x \Rightarrow x=\dfrac{3}{2}$