Giải hệ phương trình : $\left\{ \begin{array}{l}
x + y = 65\\
\log x + \log y  = 3
\end{array} \right.$

Hệ $\Leftrightarrow\begin{cases} x+y=65\\\log(xy)=3\end{cases}\Leftrightarrow\begin{cases} x+y=65\\ xy=10^3\end{cases}$

$\Leftrightarrow\left[\begin{array}{I} x=40,y=25\\ x=25,y=40\end{array}\right.$
1
phiếu
1đáp án
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Giải các hệ :
$\begin{array}{l}
1)\,\,\,\,\left\{ \begin{array}{l}
{2^{{{\log }_{\frac{1}{2}}}\left( {x + y} \right)}} = {5^{{{\log }_5}\left( {x - y} \right)}}\\
{\log _2}x + {\log _2}y = \frac{1}{2}
\end{array} \right.\\
2)\,\,\,\left\{ \begin{array}{l}
{\log _2}xy.{\log _2}\frac{x}{y} =  - 3\\
\log _2^2x + \log _2^2y = 5
\end{array} \right.\\
3)\,\,\,\left\{ \begin{array}{l}
{x^2} = 1 + 6{\log _4}x\\
{y^2} = {2^x}.y + {2^{2x + 1}}
\end{array} \right.\\
4)\,\,\,\left\{ \begin{array}{l}
{\log _2}x + {\log _4}y + {\log _4}z = 2\\
{\log _3}y + {\log _9}z + {\log _9}x = 2\\
{\log _4}z + {\log _{16}}x + {\log _{16}}y = 2
\end{array} \right.
\end{array}$
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Giải hệ phương trình, bất phương trình mũ, logarit bằng pp đại số

Cô: Trần Thị Huế - Môn: Toán học
0
phiếu
1đáp án
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 Giải các hệ  :
$1)\,\,\,\left\{ \begin{array}{l}
\frac{1}{{4\sqrt 3 }} = {\left( {x + y} \right)^{\frac{1}{{x - y}}}}\\
\left( {x + y} \right){.2^{y - x}} = 48
\end{array} \right.\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2)\,\,\left\{ \begin{array}{l}
{\left| x \right|^y} = 9\\
{\left( {324} \right)^{\frac{1}{y}}} = {2.9^{\frac{2}{y}}}
\end{array} \right.$
0
phiếu
1đáp án
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Giải các hệ :
$1)\,\,\,\left\{ \begin{array}{l}
{x^{y + 4x}} = {y^{5\left( {y - \frac{x}{3}} \right)}}\\
{x^3} = {y^{ - 1}}
\end{array} \right.$              $2)\,\,\left\{ \begin{array}{l}
{y^{\frac{1}{2}}} = {x^{ - 1}}\\
{\left( {xy} \right)^x}.{x^{ - y}} = {y^{\frac{{28x - 7y}}{2}}}
\end{array} \right.$
0
phiếu
1đáp án
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Giải các hệ :
$1)\,\,\,\,\,\,\left\{ \begin{array}{l}
{3^x}{.2^y} = \frac{1}{9}\\
y - x = 2
\end{array} \right.\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2)\,\,\,\left\{ \begin{array}{l}
{2^y} = {200.5^x}\\
x + y = 1
\end{array} \right.$

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