Giải các hệ :
$\begin{array}{l}
1)\,\,\,\left\{ \begin{array}{l}
{\log _x}\left( {x + 2} \right) >
2\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\
{\log _2}{2^{x - 1}} + {\log _2}\left( {{2^{x + 1}} + 1} \right) < {\log _2}\left( {{{7.2}^x} + 12}
\right)\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array} \right.\\
2)\,\,\,\left\{ \begin{array}{l}
{\log _{7 - x}}\left( {y - 4} \right) < 0\\
{\log _{y - 1}}\left( {3 - x} \right) < 0
\end{array} \right.
\end{array}$
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Giải các hệ :
$\begin{array}{l}
1)\,\,\,\,\,\left\{ \begin{array}{l}
{3^{\left| {{x^2} - 5x + 6} \right| - {{\log }_3}2}} = {2^{ - y - 1}}\\
2\left| {y + 2} \right| - 5\left| y \right| - {\left( {y - 3} \right)^2} \ge - 5
\end{array} \right.\\
2)\,\,\,\,\,\left\{ \begin{array}{l}
{4^{\left| {{x^2} - 8x + 12} \right| - {{\log }_4}7}} = {7^{2y - 1}}\\
\left| {y - 3} \right| - 3\left| y \right| - 2{\left( {y + 1} \right)^2} \ge 1
\end{array} \right.\\
3)\,\,\,\,\,\,\left\{ \begin{array}{l}
{5^{\left| {{x^2} - 5x + 4} \right| - {{\log }_5}2}} = {2^{y - 3}}\\
3\left| y \right| - \left| {y + 1} \right| + {\left( {y - 2} \right)^2} \le 3
\end{array} \right.
\end{array}$
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Giải hệ :
$\left\{ \begin{array}{l}
{2^{\left| {{x^2} - 2x - 3} \right| - {{\log }_2}3}} = {3^{ - y -
4}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\
4\left| y \right| - \left| {y - 1} \right| + {\left( {y + 3} \right)^2} \le
8\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array} \right.$
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Giải hệ :
$\left\{ \begin{array}{l}
\log _2^2x - {\log _2}{x^2} < 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\\
\frac {x^3}{3} - 3{x^2} + 5x + 9 > 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)
\end{array} \right.$
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