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Giải các phương trình:
$a) log_3(x+1) + log_5(2x+1) = 2\,\,\,\,\,(1)$
$b) x+ log(x^2 – x – 6) = 4+ log(x +2) \,\,\,\,(2) $
$c) {{2}^{{lo}{{g}_{5}(x + 3)}}}{ = x}\,\,\,\,\,\,\,\,(3)$
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Giải các phương trình :
$\begin{array}{l}
1)\,{\left[ {{{\left( {{2^{\sqrt x + 5}}} \right)}^{\frac{1}{{5\sqrt x + 1}}}}}
\right]^{\frac{1}{{\sqrt x }}}} = \frac{1}{2}{.4^{\sqrt x
}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,
\,\,\,\,\,\,\,\,\,\,(1)\\
2)\,\,{2^{{{\log }_8}\left( {{x^2} - 6x + 9} \right)}} = {3^{2{{\log }_x}\sqrt x -
1}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\
,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(2)\end{array}$
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